Hi Peter,

I am not really sure what you are asking for.

Can you please provide some more detail on exactly what you need to do?

Thanks

Hi Chris, Thanks for getting back to me so quickly.  I have been asked to see if it is possible to create a string within my program to contain the physical name of the file. So for arguments sake if I have a file ACCOUNTS20250211.txt is there a way to populate a PIC X(20) string as "ACCOUNTS20250211.txt  "

Hi Peter,

Sure, you can use dynamic assignment in your select statement to assign the file to a data-item in working-storage.

       identification division.
       program-id. Program1.

       environment division.
       configuration section.
           select test-file assign to my-file-name.
       data division.
       file section.
       fd test-file.
       01 test-rec  pic x(10).
       working-storage section.
       01 my-file-name  pic x(20) value spaces.
       procedure division.
           move "ACCOUNTS20250211.txt" to my-file-name
           open output test-file

           goback.