Open as in load into a variable for working on with proc code? ($lfileload) or open as in execute the application associated with that file? (spawn) $lfileload v_variable,"c:\\test.txt" will load the contents of test.txt into the variable v_variable spawn "c:\\test.txt"  will start (presumably) notepad to edit test.txt

IvanSantana said Hi, I wonder if there are any command that opens a system file. Ex: Open the test.txt file in the c: \\

  Hi Ivan, as the answer from Lain is already trying to explain, it depends on what you are aiming to do... Try to explain it roughly and probably you'll get better answers! Gianni

There are a bunch of file management proc commands which might help.